Question
Asked Oct 28, 2019
121 views

Find an equation of the tangent line to the graph of 

y = e−x^2 at the point (4, 1/e16).
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Expert Answer

Step 1

Slope of tangent line is equal to value of the first derivative of y at given point.

 

dy
= -2xe
dx
dv
-e
= -2-4
=-8e
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dy = -2xe dx dv -e = -2-4 =-8e

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Step 2

So the equation of the line is of the form

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Step 3

Substitute the given point to ...

-4e +c
c =e16+4e
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Image Transcriptionclose

-4e +c c =e16+4e

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Tagged in

Math

Calculus

Functions