Question

Asked Feb 25, 2019

Find an nth degree polynomial function with real coefficients satisfying the given conditions

n=3, -5, and 4+3i are zeros f(2)=91

Step 1

Since ,n=3,we have to find third degree polynomial , Since -5 is its zero ,so, x+5 is its factor

As complex zeros occur in conjugate pairs .So,other factors are (x-(4+3i)) and (x-(4-3i)) ,Firstly, we find the product of these two factors as shown on board.

Step 2

Now we assume the polynomial as shown on board and substitute the given values to find a

Step 3

Substitute the value of a in f(x) ...

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