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Find d^2y/dx^2 as a function of t, for the given  parameteric equations written below show all workx = 2-5cos(t)y = 1 + cos^4(t)

Question

Find d^2y/dx^2 as a function of t, for the given  parameteric equations written below show all work

x = 2-5cos(t)

y = 1 + cos^4(t)

check_circleAnswer
Step 1

From the parametric equation, the derivative...

Differentiate x with respect to t
Differentiate y with respect to t
x 2 5 cost
y=1cost
dx
= 5sin t
dt
dy
(1)
=-4 cos3 tsint
dt
dy
as follows
dr
Compute
dy
-4 cos3 t sin t
dy
dt
dx
dx
5 sin t
dt
dy
4
cos't
5
dx
help_outline

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Differentiate x with respect to t Differentiate y with respect to t x 2 5 cost y=1cost dx = 5sin t dt dy (1) =-4 cos3 tsint dt dy as follows dr Compute dy -4 cos3 t sin t dy dt dx dx 5 sin t dt dy 4 cos't 5 dx

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Math

Calculus

Derivative

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