Question
Asked Nov 24, 2019
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find dy/dx where y=sin^3x+cos^6x

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Expert Answer

Step 1

Given:

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sin xcosx y

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Step 2

Formula used:

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(x*)= dx nx

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Step 3

Hence solving the given question:&n...

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d d (y) dx (sin3 x +cos° x dy d dx d dy - (sin' x)() (cos x d ' x) (cos x) (sinx)+6(cos 3( sin2 x dx dx 3(sin2 x) (cosx) + 6 (cos" x) - (-sin x) dy (sin x-cos.x)-6(cos x-sin x) dx dy 3sin x cosx(sin.x -2 cos x dx

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Math

Calculus

Derivative

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