Question

Asked Oct 20, 2019

Find equations of both lines that are tangent to the curve y = x^{3} - 3x^{2} + 3x - 3 and are parallel to the line 3x - y = 15.

Step 1

The given curve is represented by y = x^{3} - 3x^{2} + 3x - 3 and are parallel to the line 3x - y = 15.

Slope of line 3x-y=15 is given by,

Step 2

Since the slope of the parallel lines are equal so, the slope of the tangent line will be equal to 3.

Now differentiate the given curve with respect to x in order to find the slope using the curve equation.

Step 3

Now equate both the slope...

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