Question
Asked Dec 4, 2019
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Find f
f(0) = 2, f '(0) = 1
f "(0) sin 0 + cos 0,
f(0)
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Find f f(0) = 2, f '(0) = 1 f "(0) sin 0 + cos 0, f(0)

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Expert Answer

Step 1

Given that

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"(0)=sin 0cos e

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Step 2

Integrate both side with ...

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f'(e)="(0)de f'(0)= (sin +cos 0) do f'(e)=cos (0)+sin (0)+c Since at 0 0, f'=1 Therefore f(0)cos (0)+sin(0)+ c 1 =-10 c c 2 .f'(0)=-cos (0)+ sin (0)+2

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Tagged in

Math

Calculus

Integration