Question
Asked Nov 17, 2019
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Find f iff"(t) 2e 3 sin(t), f(0)= 5, f(n) 2
f(t)
=
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Find f iff"(t) 2e 3 sin(t), f(0)= 5, f(n) 2 f(t) =

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Expert Answer

Step 1

Please see the white board. C1 is the constant of integration.

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f"(t) = 2e 3sin(t) [2e+ 3sin(t)]dt f'(t) 2e' - 3cos(t) + C1

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Step 2

Please see the white board. C2 is the constant of integration.

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f (t) f'Cdt 3cos (t)Cldt [2e = 2e - 3sin(t) + C\t + C2

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Step 3

f(t) = 2et - 3sin(t) + C1t + C2

f(0) = 2 + C2 = 5 Hence, C2 = 5 - 2 = 3

f(π) =2eπ -3sin(π) + C1π + C2 = 2eπ + C1π + 3 = 2

Hence, C1 = (2 &ndash...

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Tagged in

Math

Calculus