Question
Asked Oct 13, 2019
Find f'(x) and find the equation of the line tangent to the graph of f at x=
f(x)
(2 + 3x)(6-5x)
f'(x)-
y
Enter your answer in each of the answer boxes.
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Find f'(x) and find the equation of the line tangent to the graph of f at x= f(x) (2 + 3x)(6-5x) f'(x)- y Enter your answer in each of the answer boxes.

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Expert Answer

Step 1

Given:

S(x) - (2+3х)(6- 5х) atx 3D1
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S(x) - (2+3х)(6- 5х) atx 3D1

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Step 2

First, find the value of y for (1, y) to be on the graph of the function:

y f(x)(2+3x)(6-5x)
y fl)(2+3x1)(6-5x1)
y f)(2+3) (6-5)
y f(1) 5x1
y = 5
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y f(x)(2+3x)(6-5x) y fl)(2+3x1)(6-5x1) y f)(2+3) (6-5) y f(1) 5x1 y = 5

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Step 3

Differentiate f (x) with respe...

f(x)-(2+3x)(6-5x)
f (x) 2.6-2.5x + 3x 6-3x 5x
f(x) 12-10x18.r-15x2
f(x)= 12+8.x-15x
(12)()(15)
d
d
(15x2)
f'(x)
dx
dx
f (x) 8-30x
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f(x)-(2+3x)(6-5x) f (x) 2.6-2.5x + 3x 6-3x 5x f(x) 12-10x18.r-15x2 f(x)= 12+8.x-15x (12)()(15) d d (15x2) f'(x) dx dx f (x) 8-30x

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Math

Calculus

Derivative

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