find Fy = T − mg = ???, Evaluate the scale reading (in N) from Equation (1) if a is upward, Evaluate the scale reading (in N) from Equation (1) if a is downward, and suppose that during the launch of a rocket from the surface of the Earth, an astronaut onboard the rocket stands on a bathroom scale and measures her weight to be 3.6 times her normal weight. Determine the magnitude of the acceleration of the rocket (in m/s2).

An Introduction to Physical Science
14th Edition
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Chapter3: Force And Motion
Section3.1: Force And Net Force
Problem 2PQ: What is the condition for motion when more than one force acts?
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find Fy = T − mg = ???, Evaluate the scale reading (in N) from Equation (1) if a is upward, Evaluate the scale reading (in N) from Equation (1) if a is downward, and suppose that during the launch of a rocket from the surface of the Earth, an astronaut onboard the rocket stands on a bathroom scale and measures her weight to be 3.6 times her normal weight. Determine the magnitude of the acceleration of the rocket (in m/s2).

 

 
A person weighs a fish of mass m on a spring scale attached to the ceiling of an elevator as illustrated in the figure.
A fish is weighed on a spring scale in an accelerating elevator car.
When the elevator accelerates
When the elevator accelerates
upward, the spring scale reads
a value greater than the
weight of the fish.
downward, the spring scale
reads a value less than the
weight of the fish.
mg
mg
b
(a) Show that if the elevator accelerates either upward or downward, the spring scale gives a reading that is different from the weight of the fish.
SOLUTION
Conceptualize The reading on the scale is related to the extension of the spring in the scale, which is related to the force on the end of the spring. Imagine that the fish is hanging on a string attached to the end of the spring. In this case, the magnitude of the
force exerted on the spring is equal to the tension T in the string. Therefore, we are looking for T. The force T pulls down
on the string and pulls up
on the fish.
Categorize We can categorize this problem by identifying the fish as a particle in equilibrium
if the elevator is not accelerating or as a particle under a net force
if the elevator is accelerating.
Analyze Inspect the diagrams for forces acting on the fish in the figure and notice that the external forces acting on the fish are the downward gravitational force F, = mg and the force T exerted by the string. If the elevator is either at rest or moving at constant
velocity, the fish is a particle in equilibrium, so F, = T- F, = 0 or T = F, = Q, where Q is equal to which of the following expressions?
m
O mg
Transcribed Image Text:A person weighs a fish of mass m on a spring scale attached to the ceiling of an elevator as illustrated in the figure. A fish is weighed on a spring scale in an accelerating elevator car. When the elevator accelerates When the elevator accelerates upward, the spring scale reads a value greater than the weight of the fish. downward, the spring scale reads a value less than the weight of the fish. mg mg b (a) Show that if the elevator accelerates either upward or downward, the spring scale gives a reading that is different from the weight of the fish. SOLUTION Conceptualize The reading on the scale is related to the extension of the spring in the scale, which is related to the force on the end of the spring. Imagine that the fish is hanging on a string attached to the end of the spring. In this case, the magnitude of the force exerted on the spring is equal to the tension T in the string. Therefore, we are looking for T. The force T pulls down on the string and pulls up on the fish. Categorize We can categorize this problem by identifying the fish as a particle in equilibrium if the elevator is not accelerating or as a particle under a net force if the elevator is accelerating. Analyze Inspect the diagrams for forces acting on the fish in the figure and notice that the external forces acting on the fish are the downward gravitational force F, = mg and the force T exerted by the string. If the elevator is either at rest or moving at constant velocity, the fish is a particle in equilibrium, so F, = T- F, = 0 or T = F, = Q, where Q is equal to which of the following expressions? m O mg
O mg
(Remember that the scalar mg is the weight of the fish.)
Now suppose the elevator is moving with an acceleration a relative to an observer standing outside the elevator in an inertial frame (see the figure). The fish is now a particle under a net force.
Apply Newton's second law to the fish. (Assume that the fish is in figure (a). Use the following as necessary: m, g, and a.)
E =T- mg =
Solve for T:
(1)
T = may
+ mg =
where we have chosen upward as the positive y-direction. We conclude from Equation (1) that the scale reading Tis greater than v
the fish's weight mg if a is upward, so a, is positive (figure (a)), and that the reading is less than
v mg if a is
downward, so a, is negative (figure (b)).
(b) Evaluate the scale readings for a 42.0-N fish if the elevator moves with an acceleration a, = ±2.52 m/s?.
SOLUTION
Evaluate the scale reading (in N) from Equation (1) if a is upward:
T =
Evaluate the scale reading (in N) from Eguation (1) if a is downward:
T =
Finalize Take this advice: if you buy a fish in an elevator, make sure the fish is weighed while the elevator is either at rest or accelerating downward! Furthermore, notice that from the information given here, one cannot determine the direction of the velocity of
the elevator.
EXERCISE
Suppose that during the launch of a rocket from the surface of the Earth, an astronaut onboard the rocket stands on a bathroom scale and measures her weight to be 3.6 times her normal weight. Determine the magnitude of the acceleration of the rocket (in m/s?).
Hint
|m/s²
Transcribed Image Text:O mg (Remember that the scalar mg is the weight of the fish.) Now suppose the elevator is moving with an acceleration a relative to an observer standing outside the elevator in an inertial frame (see the figure). The fish is now a particle under a net force. Apply Newton's second law to the fish. (Assume that the fish is in figure (a). Use the following as necessary: m, g, and a.) E =T- mg = Solve for T: (1) T = may + mg = where we have chosen upward as the positive y-direction. We conclude from Equation (1) that the scale reading Tis greater than v the fish's weight mg if a is upward, so a, is positive (figure (a)), and that the reading is less than v mg if a is downward, so a, is negative (figure (b)). (b) Evaluate the scale readings for a 42.0-N fish if the elevator moves with an acceleration a, = ±2.52 m/s?. SOLUTION Evaluate the scale reading (in N) from Equation (1) if a is upward: T = Evaluate the scale reading (in N) from Eguation (1) if a is downward: T = Finalize Take this advice: if you buy a fish in an elevator, make sure the fish is weighed while the elevator is either at rest or accelerating downward! Furthermore, notice that from the information given here, one cannot determine the direction of the velocity of the elevator. EXERCISE Suppose that during the launch of a rocket from the surface of the Earth, an astronaut onboard the rocket stands on a bathroom scale and measures her weight to be 3.6 times her normal weight. Determine the magnitude of the acceleration of the rocket (in m/s?). Hint |m/s²
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