Question
Asked Feb 26, 2019
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find g'

g(x)= square root of 1-sin^2(x)

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Expert Answer

Step 1

The given expression is: g(x)= square root of 1-sin^2(x)

I am interpreting it to be as shown on the white board. 

 

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Step 2

Recall the famous formula of trigonometry: sin2x + cos2x = 1

Hence, 1 - sin2x = cos2x

Hence, the given expression takes the shape as shown on white board. 

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Step 3

Hence, g(x) = cosx

Recall that d(cosx) / dx = ...

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Math

Calculus

Derivative

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