find integral csc 3 u  sec u du

Q: Evaluate the integral. T/3 2 sin(8) + 2 sin(8) tan2(0) sec2(8) de

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Q: Evaluate the integral.

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Q: Evaluate the integral. * T/3 3 sec 0 tan 0 de In/4

A: Given that the integral is ∫π4π33secθtanθdθ. It is required to evaluate the given integral…

Q: 3 sin 3 ycos ydy

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Q: Evaluate the integral, 12 sec(4t) dt 2+3 tan (4t) dt = 2+3 tan (4t)

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Q: (1 point) Evaluate the integral by making the given substitution. dx (3x + 14)4 3x +14 u

A: Using integration by substitution

Q: Find integral.

A: In calculus, an integral is a mathematical object that can be interpreted as an area or a…

Q: Compute the definite integral.

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Q: Evaluate the integral. 10 sec 2(5t) dt J7+2 tan (5t)

A: We have to integrate the  I=∫10 sec2(5t)7+2tan(5t)dt

Q: .3 S cos³xVsinx dx

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Q: Evaluate the integral. | sec (3x +2) dx sec (3x + 2) dx =

A: Let 3x+2 = t

Q: Evaluate the integral  ∫(7(1-tan^2(x)/sec^2(x)) dx

A: We have to evaluate ∫71-tan2(x)sec2(x) dx

Q: Evaluate the integral: CT/2 cos² (4x) sin³ (4x) dx.

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Q: evaluate the integral 6x cos (5x) dx

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Q: 1 x² cos(x³) dx CoS

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Q: Evaluate the integral. "T/3 8 sec 0 tan 8 de IT/4

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Q: sin 50 do 1+ cos 50 Evaluate the integral using the substitution u = 1+ cos 50. sin 50 do 1+ cos 50…

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Q: Evaluate the integral. 5, sec 3x tan 3x dx sec $3x tan 3x dx =D

A: To evaluate: I=∫sec53x tan 3x dx=∫sec43x sec 3x tan 3x dx

Q: Evaluate the integral ∫ dx / 3−2sinx.

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Q: 3 3+ Vx dx

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Q: tan r sec r

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Q: calculate the integral.

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Q: Scos -de cos

A: We have to evaluate the integral ∫cos3θ3dθ.

Q: Evaluate the integral. 24. '8 -2/3 dx

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Q: Evaluate the integral. 1/6 dx = 5x J1/13

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Q: Compute this integral ∫ (xsin^2(x)cosx) dx

A: We use integration by parts

Q: cos 3x cos 4x dx

A: ∫cos3xcos4xdx here we use formula  2cosxcosy = cos(x+y) +cos(x-y) here x = 4x      y = 3x

Q: Evaluate integral of {1/(x^2-9)^(3/2)} dx  Using trigonometric substitution

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Q: the integral of tan^2x cos^3xdx

A: we have to find integral of tan^2xcos^3xwe use following rule

Q: Evaluate the integral (2³ + 1)'/³,³dx.

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Q: Evaluate the integral  ∫tan^3(x)sec^6(x) dx

A: The trigonometric Identity is sec2 x=1+tan2 x. The property of the indefinite integral is…

Q: sec (7x)tan' (7х)dx

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Q: sec 3B tan 3BdВ

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Q: 16. tan's cos's da

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Q: sec* 0 tan“ Od0

A: Using Substitution,

Q: Evaluate the integral. sec 0(sin 0 cos 0 + cos 0) de Jo

A: Let I=∫0π/2secθsinθcosθ+cosθdθ

Q: Evaluate the integral (2х + 6)dx х2 — 2х + 17

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Q: sec 2x CSC 2%

A: Solution: Consider the given integral: Now, rewrite the integral: Let u = cos 2x

Q: Evaluate the integral sec2 2x tan 2ædx

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Q: Evaluate the integral. * /4 2 sec (0) tan4(0) de

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Q: Evaluate the integral. 34 1 8- dx

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Q: Evaluate the integral. "T/3 9 sin(0) + 9 sin(0) tan2(0) sec2(0) do

A: The given integral is ∫0π39sinθ+9sinθtan2θsec2θdθ

Q: /2 12 (siny kpxp

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Q: find integral csc 3 u du

A: Consider the given: ∫csc3uduApply Reduction…

Q: Evaluate the integral. "1/3 tan (x) sec*(x) dx

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Q: Evaluate the integral. Tt/3 3 tan (x) sec (x) dx

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Q: Evaluate the integral. • T/4 sec*0 tan40 de

A: Given :

Q: Evaluate the integral. T/3 7 sin(0) + 7 sin(0) tan²(0) de sec²(0)

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Q: sec² (1+ /7) dr. 6) Use the substitution u = 1+Va to evaluate the indefinite integral|

A: