Q: Find parametric equations for the normal line to the surfacez=-7x2 -9y2 at the point (2,1,-37)
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Q: Find parametric equations for the normal line to the surface z=-7x2 -9y2 at the point (2,1,-37)
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Q: Find the tangent plane to surface 8x2 + y2 + 4z2 = 25 at the point ( 1, -1, 2 )
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Find parametric equations for the normal line to the surfacez=ln(3x2 +7y2 +1) at the point (0,0,0)
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- Find equations of (a) the tangent plane and (b) the normal line given to the surface at the specified point yz2 - ex-z = 0 (1, 1, 1)Find a set of symmetric equations for the normal line to the surface xyz = 12 at the point (2, −2, −3).The curve with parametric equationsx = t, y = 1 - cos t, 0 ≤ t ≤ 2πis called a sinusoid. Findthe point (x, y) where the slope of the tangent line is largest.
- Find the equation of the tangent line and equation of the normal line to the graph of3x cos y = 1 + x^2 +√(2y + 1) at P(1, 0). With full solution please thankyouThe curve with parametric equationsx = t, y = 1 - cos t, 0 ≤ t ≤ 2πis called a sinusoid. Findthe point (x, y) where the slope of the tangent line is smallestFind an equation of the tangent plane to the surface z = 16 − x2 − y2 at the given point (2, 2, 8) and find a set of symmetric equations for the normal line to the surface at the given point.
- Find the tangent plane to surface 8x2 + y2 + 4z2 = 25 at the point ( 1, -1, 2 ).A plane area is bounded in the first quadrant by the curves y² = -16 (x-4), the line 8x-15y = 0, and the x-axis. What is the moment of inertia of this area about the line y = -10 ?A plane area is bounded in the first quadrant by the curves y² = -16 (x-4), the line 8x-15y = 0, and the x- axis. What is the moment of inertia of this area about the line y = -10 ?