Find the an equivalent resultant force and specify the location (x,y) of the equivalent resultant force on the slab. Use both the scalar and vector formulations to work out the problem.
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- Four parallel forces act on the plate as shown. For the force system shown, find the equivalent resultant force and specify its x and y location from the origin, given: FA = 170 lbs, FB = 240 lbs, FC = 210 lbs, FD = 140 lbs, LX = 16 ft, LY = 14 ft, BY = 5 ft, DX = 6 ft The magnitude of resultant force, FR is: (positive number) FR = lbs The distance from the Origin in the positive X-direction is: X = ft The distance from the Origin in the positive Y-direction is: Y = ftThe following concurrent forces are acting on a body in xy plane: A 300 lb pointing up to the right 30 degrees with x axis, 400 lb at 45 degrees with x axis acting up to the left, 200 lb down to the left at 60 degrees with x axis, 150 lb down to the right at 75 degrees with x axis and a 100 lb directly to the right. Determine the resultant force and its direction using graphical and analytical method. Show solution, formula and the FBD and pls write legibleConsider the given values for the force system shown: xA = 9 ft xB = -12 ft xC = 7 ft yA = 3 ft yB =10 ft yC = 2 ft zA = 1 ft zB = -9 ft zC = 11 ft A. Determine the angle θ between AB and AC. B. Determine the minimum distance from point B that passes through AC.
- The following concurrent forces are acting on a body in xy plane: A 300 lb pointing up to the right 30 degrees with x axis, 400 lb at 45 degrees with x axis acting up to the left, 200 lb down to the left at 60 degrees with x axis, 150 lb down to the right at 75 degrees with x axis and a 100 lb directly to the right. Determine the resultant force and its direction using graphical and analytical method. Pls show the solution, formula and free body diagram.Lami's Therem is used to find the resultant of three coplanar concurrent forces Select one: True False1.2) Problem. 3 The following forces (all pull) act at a point : (i) 25 N due North ; (ii) 10 N North-East ; (iii) 15 N due East ; (iv) 20 N 30° East of South ; (v) 30 N 60° South of West. Find the resultant force. What angle does it make with East ?
- The process of finding the resultant force for a system of forces acting on body is called Select one: A) Resultant of forces B) Resolution of forces C) Siding Forces D) Composition of forcesconcurrent force system in space is composed of 3 forces described as follows: P, has a magnitude of 100 kN and acts through the origin and point x-3, y=4, and z=2. P₂ has a magnitude of 60 kN and acts through the origin and point x=4, y=1, and z=-2. P, has a magnitude of 80 kN and acts through the origin and point x=2, y=-3 and 2-3. Give the magnitude of the resultant force. Compute for the magnitude and direction cosines of the resultant force.Given a 2-D force system with geometry as shown. Find the magnitude of the equivalent couple moment (Nm) acting at O if P = 509 N , Q = 388 N, and T = 444 N . Round off only on the final answer expressed in 3 decimal places. Instead of units, indicate the direction of moment: use CW if clockwise , CCW if counterclockwise.
- Consider Figure 1. Determine the magnitude and direction of the resultant FR=F1+F2+F3 of thethree forces by first finding the resultant Fꞌ=F1+F2 and then finding FR=Fꞌ+F3. Specify thedirection of FR measured clockwise from the positive x-axis.1. Discuss and explain with example problem the following: a. Components of a force. b. Graphical method in finding the resultant of three or more concurrent forces. c. Analytical method in finding the resultant of three or more forces applicable to all types of force system. d. Principle of moment. e. CouplesUsing the Cartesian components (rectangular components), determine the resultant of the force vectors answering the magnitude in the space provided below and the direction in the procedure document. Only handwritten Draw to approximate scale the sum-of-forces polygon showing the original vectors and the resultant. In a separate document show the entire work. F = 252lbs, F₂ = 130lbs, a = 65° F3 = 55lbs, m = 6.2, and n = 8.6