Find the area enclosed by one leaf of the rose r=8cos(3θ).

Q: Find the area of the shaded sector. 40% V18 m

A: Solving by sector formula we have

Q: 225° 6 m

A: Given : The radius of the circle is 6 m and the angle made by the sector is 225°

Q: Find the area enclosed by one leaf of the rose r= 5 cos (70).

A:

Q: ind the area of this?

A: Here we have to Area of the triangle:-

Q: Find the area of the shaded region. -4+ 3ain e

A:

Q: Find the surface area of the figure. Round your answer to the nearest hundredth, if necessary

A: Given figure is a cuboid Surface area  of cuboid is SA=2lw+2wh+2hl Here , l=11 in w=6 in h=8 in

Q: Find the area of the shaded region of circle W below. Round your answer to the nearest tenth if…

A: This question is related to Circles, we will solve it using given information.

Q: Find the area of the composite figure shown below. T 17

A:

Q: Calculate the area of the section shown below by formulas. - Xi X2 hl h2 C W

A:

Q: Find the area of the shaded region. 3 8 yd

A:

Q: Find the length of XY and mMN.

A:

Q: Find the area of the shaded sector XYZ. Round your answer to the nearest hundre 18 yd

A:

Q: x² + y² =a²

A:

Q: find the area of the small sector 1) 11 ft 315°

A: Area of sector =πr2×θ360°                           where θ is the angle of the sector

Q: Find the value of x if ZL is the midsegment of A DNE. 20

A: To find the value of x :

Q: 8 yd

A: In a circle a triangle is formed on the diameter is always right triangle.

Q: from x-S to=8 Carand xaxis revolved find the area

A:

Q: Find the area of the shaded region. Round your answer to one decimal place.

A: To find the area of the shaded region.

Q: Find the area of shaded sector, round your answer to nearest tenth. YZ = 14.2 m 87

A:

Q: The diameter of a circle is 18 in. Find its area in terms of T.

A: Given diameter : d=18 inch Hence, radius of given circle is : r=d2=182=9 inch

Q: 5 8 tm

A:

Q: The second-quadrant area enclosed by x²- y² = 25.

A:

Q: 0= 315. e is located in quadrant O II O IV

A:

Q: Find the area of the shaded region below, given that AT = 10 and CA = 24. Round your answer to the…

A: Angle subtended by diameter at any point on the circle is 90 degrees

Q: Find the area of the figure below. Round to the nearest tenth if necessary. 3D 3D 7 m 18 m

A: 1) 2*area of semicircle + area of rectangle => 2(Pi*r*r)/2 + l*w => Pi*r*r+ l*w =>…

Q: Find the area of the shaded region in the figure. (Round your answer to one decimal place.) 430.4 |×…

A: in a given circle we have  r=12 ,θ=π3 s=?

Q: h b Find the area of the triangle above.

A: Given, A right angle triangle with  Base = b  Height = h  We have to find the area of triangle.

Q: Find 2-x) dx by using the formula for the area of a triangle.

A: Given, ∫022-xdx  We have to find the above definite integral by using area of triangle .

Q: Find the order and degree MN olx dx2

A:

Q: Find the area of the shaded region in the figure. (Round your answer to one decimal place.) 430.4 |×…

A: From the given figure: The radius of the circle is 12 Formula used: Area of circle =πr2Area of…

Q: The value of f -csc(3x)cot(3x)dx is

A: We have to find integral in this question.

Q: 2.

A:

Q: Find the area blw y=5-4x and -x2+45 round answSer to 2 decimal places

A:

Q: Find the area of Circle S. R. P. 135 A 48 ft2 Area of Circle S =

A: Area of sector = θ360πr2

Q: Find the area of the shaded region. Leave your answer in terms of T. 1000 12ft O 20T/3 ft2 O 20n ft?…

A:

Q: Find the area of the shaded sector. Round your answer to the nearest hundredth. F 240° 7 in. E

A:

Q: calculate the area R

A:

Q: H. 4) F J 2012=16inc Radius: Diameter: 20 inches Circumference: 319X30-62. Area:

A:

Q: the ratio d/dx 8csc(x)/csc(x)cot(x) is a constant number. Its value is

A:

Q: R 4 m

A: The given figure is  The main objective is to calculate the area of the shaded region.

Q: 9. 11 3

A:

Q: 10 in. 60° F D 3) What is the Area of the Sector above?

A:

Q: Find the area of the sector. 13 ft 270 398.0 ft? O 159.0 ft2 381.7 ft? O 158.4 ft2

A: The solution is given below.

Q: Find area inside out Side r=2c0s6 ra I

A: Given polar equations are r=2cosθ and r=1 Consider first polar equation r=2cosθ Multiply with r on…

Q: What's the area of the figure?

A: Given figure is trapezoid with length of parallel sides is 12 cm and 20 cm and height is 5 cm. Now…

Q: Find the area enclosed by one leaf of the rose r= 8 cos (50).

A: Given: r=8 cos 5θ To find: The area enclosed by one leaf.

Q: D 5 сm C 25 сm

A:

Q: Mrs smith asked the class to find the area of this figure. What answer should the students come up…

A:

Q: Find the area K of the triangle. a= 4, b 10, C = 25° square units (Round to two decimal places as…

A:

Q: find the lateral area of the figures in terms of pi.

A:

Optimization

Optimization comes from the same root as "optimal". "Optimal" means the highest. When you do the optimization process, that is when you are "making it best" to maximize everything and to achieve optimal results, a set of parameters is the base for the selection of the best element for a given system.

Integration

Integration means to sum the things. In mathematics, it is the branch of Calculus which is used to find the area under the curve. The operation subtraction is the inverse of addition, division is the inverse of multiplication. In the same way, integration and differentiation are inverse operators. Differential equations give a relation between a function and its derivative.

Application of Integration

In mathematics, the process of integration is used to compute complex area related problems. With the application of integration, solving area related problems, whether they are a curve, or a curve between lines, can be done easily.

Volume

In mathematics, we describe the term volume as a quantity that can express the total space that an object occupies at any point in time. Usually, volumes can only be calculated for 3-dimensional objects. By 3-dimensional or 3D objects, we mean objects that have length, breadth, and height (or depth).

Area

Area refers to the amount of space a figure encloses and the number of square units that cover a shape. It is two-dimensional and is measured in square units.