Question

Asked Nov 11, 2019

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Find the area enclosed by the given curve and the y-axis.

x = t2 − 3t

y = square root of t

Step 1

From y=sqrt(t) find t=y^2

Then plug it in x=t^2-3t

So the curve is: x=y^4-3y^2

Step 2

We graph the curve and y axis.

Step 3

Plug x=0 in x=y^4-3y^2 to find where they cuts each other. y= -sqrt(3) ...

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