Find the derivative of f(x)=(sinxcosx)1/2
Given the function,
f(x)(sinxcos x)
We have the identity
2sin rcosx sin(2x) sin (2x) sin xcosx= 2 sin(2x) Then the function can be written as f(x) = 2
Differentiate the ab...
d sin (2x) f'(x)= dx 2 Let us apply the chain rule. df (u)_df_du dx du dx sin(2x Let f u, where 2 df Then, 1 1 du 2 2u2 du 2cos(2x) cos(2x) And dic 2
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