Question
Asked Nov 26, 2019
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Find the derivative of the function:

f(x)=ln  (x-3)^2÷(2x-1)^3

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Given function is,&...

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(х-3)* f(x) (2х - 1)" Compute the derivative of the given function as follows x) = (x-3)2 (2х -1)° f'(x) (2x-1)' (s-3))-(x-3)(2-1) (2x-1)') (2x-1) (2(x-3))-(x-3) (3(2x-1)' (2)) _ (2х - 1)" (2x-1)(x-3)-6(x-3) (2x -1) (2x-1)

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Calculus

Derivative

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