Question
Asked Oct 17, 2019
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problem in photo attached

Find the derivative of the function
Зxх
u2-4
du
u24
g(x) =
2х
g'(x)
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Find the derivative of the function Зxх u2-4 du u24 g(x) = 2х g'(x)

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Expert Answer

Step 1

Given a function,

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Step 2

To find the derivative of the function:

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Step 3

Using the above rule, we su...

-3x u2 - 4
g'(x)
dx
du
u2 4
2x
d
d
(2х) +
dx
= g(x, 3x)
(3х) — g(х, 2x)
dx
dr g(x, u)du
-3х а /u?
(2x)2 4
3
(3х)2 — 4
(3х)2 + 4
4*
du
axu24
2 +
(2x)24
2x
9х2 — 4
*3
9x2 4
4x2 4
d
o)
(constant)
dx
0 du.
2 +
= )
4x2 4
2x
9х2
4(х2 — 1)
3
4(x2 1)
*2
9x2 4
(x2 1)
- 2
(x21)
9x2
= 3
9x2 4
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-3x u2 - 4 g'(x) dx du u2 4 2x d d (2х) + dx = g(x, 3x) (3х) — g(х, 2x) dx dr g(x, u)du -3х а /u? (2x)2 4 3 (3х)2 — 4 (3х)2 + 4 4* du axu24 2 + (2x)24 2x 9х2 — 4 *3 9x2 4 4x2 4 d o) (constant) dx 0 du. 2 + = ) 4x2 4 2x 9х2 4(х2 — 1) 3 4(x2 1) *2 9x2 4 (x2 1) - 2 (x21) 9x2 = 3 9x2 4

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Tagged in

Math

Calculus