Question
Asked Nov 3, 2019
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Find the derivative of the function.

f(x) = (2x − 3)4(x2 + x + 1)5
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Expert Answer

Step 1

Given function is

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x+1) f(x) (2x-3)'(x2+x+

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Step 2

We will find f'(x) by using product rule of differentiation  , which states that if f=uv, then f'=uv'+vu'

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d 5 (x)(2x-3)x+x+1} +(x +x+1) d(2x-3) dc

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Step 3

Now, we will use the result that derivative o...

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r)-(2x-3's(x) x4(2-3) d (2-3) f ()-5(2x-3) (x2 + x+1) (2x +1)+ 4(x2 +x+1)} (2x -3)' (2) r(x)-(2x-3)(x)[5(2x -3)(2x -1)-8(x +x +1)] ()(2x-3) (x)'[5(4x -4x -3)-8( + x +1)] r(x)(2x-3) 1) (28 -12x -7) +x +1)+(x +x+14(2x -3)(2x -3) +4(x2 +x+1)(2x - 3) (2) = = _

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Tagged in

Math

Calculus