Find the ΔH (in kJ) for the reaction: PCl3(l)  +  Cl2(g)  →  PCl5(s)   Given: 2 P (s)  +  3 Cl2(g)  →  2 PCl3(l)                 ΔH = -640 kJ 2 P (s)  +  5 Cl2(g)  →  2 PCl5(s)                ΔH = -886 kJ

Chemistry: Matter and Change
1st Edition
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Chapter15: Energy And Chemical Change
Section15.2: Heat
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Find the ΔH (in kJ) for the reaction: PCl3(l)  +  Cl2(g)  →  PCl5(s)

 

Given:

2 P (s)  +  3 Cl2(g)  →  2 PCl3(l)                 ΔH = -640 kJ
2 P (s)  +  5 Cl2(g)  →  2 PCl5(s)                ΔH = -886 kJ

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