Find the energy stored in the magnetic field of an indicator having inductance 12.5 mH carrying the current 2.67A.

Q: Suppose that a rectangular toroid has 1500 windings and a self-inductance of 0.04 H. If the height…

A: Given : Number of turns, N= 1500 Self Inductance, L =0.04 H Height , h = 0.08 m  Energy stored , U=…

Q: At the instant a current of 0.80 A is flowing through a coil of wire, the energy stored in its…

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Q: Find the induced emf in the coil as a function of time if f=10 Hz.

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Q: Find the magnetic energy stored by a 4.94 mH inductor when the current through it is 1.3 A.

A: Given data:  Inductance (L) = 4.94 mH = 4.94×10-3 H Current (I) = 1.3 A Required: The magnetic…

Q: A solenoid of radius 1.50 cm has 620 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…

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Q: Find the induced emf when the current in a 48.0-mH inductorincreases from 0 to 535 mA in 15.5 ms

A: The induced emf can be given by ε=-LdIdt

Q: Derive the self-inductance for a rectangular toroid

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Q: An emf of 8V is induced in a given coil when the current in it changes at the rate of 32 A/ sec.…

A: Given data:   Induced emf, ε=8V    Current, dIdt= 32 A/sec

Q: Find the magnetic energy stored by a 4.94 mH inductor when the current through it is 10.3 A.

A: Given: The inductance of the inductor is 4.94 mH. The electric current is 10.3 A.

Q: A solenoid of radius 3.30 cm has 800 turns and a length of 15.0 cm. (a) Find its inductance. mH (b)…

A: Given:      Radius of the solenoid, r = 3.3 x 10-2 m…

Q: Find the induced current in the loop, in amperes, at time t = 0.102 s.

A: Induced current is induced emf devided by Resistance , whereas induced emf is given by rate of…

Q: Find the cross-sectional area of a 5.1 cm long solenoid with 480 turns and a self-inductance of 44…

A: Length (L) = 5.1 cm = 0.051 m Number of turns (N) = 480Self inductance = 44 μH

Q: Find the cross-sectional area of a 5.3 cm long solenoid with 550 turns and a self-inductance of 43…

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Q: A solenoid of radius 1.50 cm has 620 turns and a length of 25.0 cm. (a) Find its inductance. mH (b)…

A: Write the given values with the suitable variables. r=1.50 cm=1.5×10-2 mN=620l=25 cm=0.25 mε=90…

Q: Calculate the peak output voltage of a simple generatorwhose square armature windings are 6.60 cm on…

A: Given:- number of turns N = 125 loops    magnetic field B = 0.200 Tesla          frequency ω = 120…

Q: A solenoid of radius 3.5 cm has 800 turns and a length of 25 cm. (a) Find its inductance. mH (b)…

A: Given: The radius of the solenoid is 3.5 cm = 0.035 m.                                  { 1 cm =…

Q: A 10 H inductor carries a current of 20 A ch ice at 0°C could be melted by the energy stored in…

A: Latent heat is the energy absorbed or released by a substance during a change in its physical state…

Q: find the induced  emf in the wire over a time of 0.3 sec.

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Q: A 300 turns coil is cut perpendicular to the changing magnetic flux of 0 Wb to 50 mWb in 0.1 s. Find…

A: emf =enumber of turns= nchange in mag. flux=∆ϕchange in time= ∆t

Q: A solenoid of radius 4.5 cm has 800 turns and a length of 25 cm. (a) Find its inductance. mH (b)…

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Q: On which factors does the magnetic field of a solenoid depends?

A: Standard expression for the magnetic field (B) of a solenoid is given as, B=μ0×N×iL…

Q: A 298 turn solenoid has a radilus of 4.95 cm and a length of 19.5 cm. (a) Find the inductance of the…

A: Formula of inductance of solenoid is as follows: L=μ0N2Al…

Q: (Electrodynamıcs) Find the self-inductance of a torroidal coil wath rectangular cross section (inner…

A: Given:- The magnetic field inside the toroid is given as  B=μ0NI2πs Find:- The self-inductance of a…

Q: A solenoid is made from a wire wound around a tube 36.0 cm long having a diameter of 8.00 cm. If…

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Q: Find the egergy stored in the magnetic filed of an inductor having inductance 12.5mH. Carrying the…

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Q: Find the inductance and induced emf for a solenoid with a cross-sectional area of 1.3 × 10-3m2. The…

A: Given: Cross-sectional area of solenoid = 1.3×10-3 m2. Length of solenoid l = 9.0 cm. = 9×10-2 m.…

Q: Find the magnetic energy stored by a 5.22 mH inductor when the current through it is 11.1 A.

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Q: Find the energy stored in the magnetic field of an inductor having inductance 12.5 mH carrying the…

A: The expression for the stored energy is,

Q: A solenoid of radius 1.70 cm has 480 turns and a length of 15.0 cm. (a) Find its inductance.(in mH)…

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Q: Calculate the inductance (H) of an air cored coil that has a length of 11 cm, a core with…

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Q: Find the magnetic energy stored by a 5.24 mH inductor when the current through it is 10.7 A.

A: Given GivenL=5.24 mH = 5.24 ×10-3 HI =10.7 A

Q: A solenoid with a cross-sectional area of 1.14 * 10-3m2 is0.610 m long and has 985 turns per meter.…

A: Area, A = 1.14 x 10-3 m2  length, l = 0.61 m  number of turns per unit length, n = 985 per m change…

Q: A solenoid of radius 2.30 cm has 440 turns and a length of 25.0 cm. (a) Find its inductance.…

A: Given: A solenoid of radius r = 2.30 cm = 0.023 m; Number of turns N = 440  and a length of l = 25.0…

Q: At the instant a current of 0.90 A is flowing through a coil of wire, the energy stored in its…

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Q: A solenoid has a length of 20 cm, a radius of 0.8 cm, and 350 turns, and carries a 2.9-A current.…

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Q: A 300-turn solenoid has a radius of 5.00 cm and a length of20.0 cm. Find (a) the inductance of the…

A: The expression for the inductance of the solenoid is given by,

Q: The magnetic flux associated with a coil moving in a magnetic field changes according to the…

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Q: An ideal air-core solenoid has a length of 6.5 cm, area of 2 cm2 and 3000 turns. Find the…

A: Given values: Length, l=6.5 cm Area, A=2 cm2 Number of turns, N=3000 turns

Voltage Across Inductor

An actor is a passive electrical component that consists of a coil bent in the form of wire which uses electromagnetism to produce electric current through the coil. When the electric current flows through a conductor that is the coil, a magnetic flux is developed around the conductor. This flow of current through the coil creates a magnetic field based on Fleming's Right-hand thumb rule. If there is any decrease in the current passing through the inductor, then the magnetic field will also decrease and energy is released through the generation of electric current. There is also a secondary voltage inducing in the same coil due to the magnetic flux, since it opposes any changes in the electric current flowing through the circuit. An inductor is also called choke, coil, or solenoid. A choke is designed to block certain frequencies when the DC current passes. A winding coil is coated with insulation to give extra insulation and protect the circuit. They are usually tightly wrapped around a central core which is cylindrical in nature so that the magnetic flux can be induced. The solenoid is a three-dimension coil that is used to exhibit electromagnetism when the magnetic field is developed due to the current flowing through the coil. The sign convention of the inductor is the same as the power dissipating device. When the current flows into the positive side of the voltage across the inductor, the value is positive and the inductor dissipates power whereas when the inductor releases the power back to the circuit, the current has a negative sign convention.