Find the equation of the tangent line to the graph of f(x)=2xln(x+8) at x=6.
Equation of the tangent line to the curve y = f(x) at the point (a, b) will be given by
(y - b) / (x - a) = f'(x = a)
f(x) = 2xln(x+8)
a = 6
b = f(a) = 2 x 6 x ln(6 + 8) = 12 x ln(14) = 31.67
f'(x) = 2ln(x + 8) + 2x / (x + 8)
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