Question
Asked Nov 20, 2019
5 views

Find the equation of the the line perpendicular to the line (2,3) and 2y= 6-3x

check_circle

Expert Answer

star
star
star
star
star
1 Rating
Step 1

Given,

           The required equation of the line passes through the point (2, 3) and perpendicular to the line 2y = 6 - 3x.

Now,

         Let the slope of the required line be m.

Now, writing the equation of the line 2y = 6 - 3x in slope-form, we get

2у %3D 6
Зх
x 3
2.
3у 3D
So, slope of the line 2y = 6 - 3x is -3/2.
Since, required line is perpendicular to the line 2y 6- 3x
()-
1
:. т х
m=
help_outline

Image Transcriptionclose

2у %3D 6 Зх x 3 2. 3у 3D So, slope of the line 2y = 6 - 3x is -3/2. Since, required line is perpendicular to the line 2y 6- 3x ()- 1 :. т х m=

fullscreen
Step 2

Therefore, required equat...

у -3 %3D (х — 2)
2х
4
—у- 3 %3
3
3
2х
4
3
3у-
3
2х
зу
с
help_outline

Image Transcriptionclose

у -3 %3D (х — 2) 2х 4 —у- 3 %3 3 3 2х 4 3 3у- 3 2х зу с

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Math

Algebra

Equations and In-equations