Asked Nov 19, 2019

FInd the expected number of infected ducks in a sample of 5 ducks if the probability of an infected duck is .3 and the ducks are considered to be independent.


Expert Answer

Step 1

Given data

No of ducks = 5

Probability of an infected duck p = 0.3

Using Binomial theorem

Probability of x success out of n trial is given by


Image Transcriptionclose

(К)x р*x (1—р)"-* Р(х %3 х) — Drawing Probability distribution table XX Р(X) X Р(X) 0 Р(x — 0) — x 0.30 x (1 0.3)5-0 0.16807 0 1 Р(x — 1) — x 0.31 x (1 -0.3)5-1 = 0.36015 0.36015 2 x 0.32 x (1 0.3)5-2 Р(x 3 2) — 0.3087 0.6174 3 Р(X — 3) - x 0.33 x (1 -0.3) 5 -3 0.1323 0.3969 4 Р(x 3D 4) 3D (С) x 0.34 x (1 -0.3)5-4 0.02835 0.1134 5 P(X 1) ( x 0.35 x (1 -0.3)5-5 0.00243 0.01215 Sum1 1.5

Step 2

Expected number of infected ducks in a...


Image Transcriptionclose

хX Р(X) 3D 1.5 Е(X) —D


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