Question
Asked Mar 7, 2019
12 views

Find the first and second derivatives of the function.

(6t2 - 4)2 (5t2)

 

check_circle

Expert Answer

Step 1

Given function: f(t) = (6t2 - 4)2 (5t2) = (36t4 - 48t2 + 16) (5t2) = 180t6 - 240t4 + 80t2 

Recall the famous rule of differentiation: d(xn) / dx = nxn-1

Step 2

First derivative = f'(t) = df(t) / dt = 180 x 6 x t5 - 240 x 4 x t3 + 80 x 2 x t = 1,080t5 - 960t3 + 160t 

Second derivative = f''(t) = d2f(t)...

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Solutions are written by subject experts who are available 24/7. Questions are typically answered within 1 hour.*

See Solution
*Response times may vary by subject and question.
Tagged in

Math

Calculus

Derivative

Related Calculus Q&A

Find answers to questions asked by student like you
Show more Q&A
add