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Asked Sep 19, 2019
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Find the function that has an output of 16 when x=2, and has zeros 1 and −2i.

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Step 1
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The complex conjugate is also a root. Therefore, the zeros are 1, 2i and -2i. Thus, the degree of the polynomial is 3

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(x-1(x+2i) x-2i). Therefore, the polynomial is The factors of the polynomial are P(x)(x-1)(x+2i) (x-2i) -x-1)(x(2 =(x-1)(x-4) (x-1)x+4) =x3 +4x -x2-4 =x3 -x2+4x-4

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