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Asked Dec 5, 2019
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Find the inverse function f-1(x) of the function. Also, state the range of the inverse function in interval notation.

f(x)= the square root of (2+5x) , x greater than or equal to -2/5

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Step 1
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The given function is f(x) = 2+5x,x2- Let y = /2+5x. To find the inverse, interchange the variables x and y, then solve the equation for y.

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Step 2
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x= /2+5y x=(2+5y)7 x = 2+5y x²-2=5y x -2 5 Therefore, the inverse function is f(x) =

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