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Find the inverse of the function and state its domain and range. {(- 3,4),(- 1,5),(0,2),(2,6).(5,7)} O A. {(3,4), (1,5), (0,2), (– 2,6), (- 5,7)}; D= {3,1,0, – 2, – 5); R= {2,4,5,6,7} B. {(3, – 4), (1, - 5), (0, – 2), (– 2, - 6), (- 5, - 7)}; D = {3,1,0, – 2, – 5}; R={-7,-6, - 5, – 4, – 2} C. {(4, – 3), (5, - 1), (2,0), (6,2), (7,5)}; D= {2,4,5,6,7}; R={-3, – 1,0,2,5} D. {(-3, - 4), (- 1,-5), (0, – 2), (2, – 6), (5, – 7)}; D = {-3, - 1,0,2,5); R={-7,-6,-5, – 4, – 2}

Find the inverse of the function and state its domain and range. {(- 3,4),(- 1,5),(0,2),(2,6).(5,7)} O A. {(3,4), (1,5), (0,2), (– 2,6), (- 5,7)}; D= {3,1,0, – 2, – 5); R= {2,4,5,6,7} B. {(3, – 4), (1, - 5), (0, – 2), (– 2, - 6), (- 5, - 7)}; D = {3,1,0, – 2, – 5}; R={-7,-6, - 5, – 4, – 2} C. {(4, – 3), (5, - 1), (2,0), (6,2), (7,5)}; D= {2,4,5,6,7}; R={-3, – 1,0,2,5} D. {(-3, - 4), (- 1,-5), (0, – 2), (2, – 6), (5, – 7)}; D = {-3, - 1,0,2,5); R={-7,-6,-5, – 4, – 2}

Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
Big Ideas Math A Bridge To Success Algebra 1: Student Edition 2015
1st Edition
ISBN:9781680331141
Author:HOUGHTON MIFFLIN HARCOURT
Publisher:HOUGHTON MIFFLIN HARCOURT
Chapter10: Radical Functions And Equations
Section: Chapter Questions
Problem 3CT
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Find the inverse of the function and state its domain and range. {(- 3,4),(- 1,5),(0,2),(2,6).(5,7)} O A. {(3,4), (1,5), (0,2), (– 2,6), (- 5,7)}; D= {3,1,0, – 2, – 5); R= {2,4,5,6,7} B. {(3, – 4), (1, - 5), (0, – 2), (– 2, - 6), (- 5, - 7)}; D = {3,1,0, – 2, – 5}; R={-7,-6, - 5, – 4, – 2} C. {(4, – 3), (5, - 1), (2,0), (6,2), (7,5)}; D= {2,4,5,6,7}; R={-3, – 1,0,2,5} D. {(-3, - 4), (- 1,-5), (0, – 2), (2, – 6), (5, – 7)}; D = {-3, - 1,0,2,5); R={-7,-6,-5, – 4, – 2}
Transcribed Image Text:Find the inverse of the function and state its domain and range. {(- 3,4),(- 1,5),(0,2),(2,6).(5,7)} O A. {(3,4), (1,5), (0,2), (– 2,6), (- 5,7)}; D= {3,1,0, – 2, – 5); R= {2,4,5,6,7} B. {(3, – 4), (1, - 5), (0, – 2), (– 2, - 6), (- 5, - 7)}; D = {3,1,0, – 2, – 5}; R={-7,-6, - 5, – 4, – 2} C. {(4, – 3), (5, - 1), (2,0), (6,2), (7,5)}; D= {2,4,5,6,7}; R={-3, – 1,0,2,5} D. {(-3, - 4), (- 1,-5), (0, – 2), (2, – 6), (5, – 7)}; D = {-3, - 1,0,2,5); R={-7,-6,-5, – 4, – 2}
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