# Find the point of inflection of the graph of the function. (If an answer does not exist, enter DNE.)F(x)=x+2cosx, [0, 2pi]smaller x-value (x,y)=lager x-value (x,y)=Describe the concavity. (Enter your answers using interval notation. If an answer does not exist, enter DNE.)concave upward (     )concave downward (     )

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Find the point of inflection of the graph of the function. (If an answer does not exist, enter DNE.)

F(x)=x+2cosx, [0, 2pi]

smaller x-value (x,y)=

lager x-value (x,y)=

Describe the concavity. (Enter your answers using interval notation. If an answer does not exist, enter DNE.)

concave upward (     )

concave downward (     )

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Step 1

Given,

Step 2

For point of inflection, differentiate function twice help_outlineImage Transcriptionclose(x + 2cos x) f"(x) =(x+ 2cos .x) de =1- 2sin x s"(x) = (1–2sin x) de =-2 cos x fullscreen
Step 3

Now, take second derivativ... help_outlineImage Transcriptionclosef"(x)= 0 -2 cos x = 0 cos x = 0 [=zo]>=- [0, 2.7] fullscreen

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### Calculus 