Question
Asked Dec 13, 2019
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Find the point of inflection of the graph of the function. (If an answer does not exist, enter DNE.)

F(x)=x+2cosx, [0, 2pi]

smaller x-value (x,y)=

lager x-value (x,y)=

Describe the concavity. (Enter your answers using interval notation. If an answer does not exist, enter DNE.)

concave upward (     )

concave downward (     )

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Expert Answer

Step 1

Given,

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[0,27] S (x) = x + 2 cos .x ,

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Step 2

For point of inflection, differentiate function twice

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(x + 2cos x) f"(x) =(x+ 2cos .x) de =1- 2sin x s"(x) = (1–2sin x) de =-2 cos x

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Step 3

Now, take second derivativ...

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f"(x)= 0 -2 cos x = 0 cos x = 0 [=zo]>=- [0, 2.7]

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Tagged in

Math

Calculus