Question
Asked Oct 1, 2019
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Find the real solutions of equation

x4+4x3+2x2-x+6=0

 

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Expert Answer

Step 1

To determine the real solutions of given equation.

Step 2

Given equation:

x44x 2x-x+6 = 0
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x44x 2x-x+6 = 0

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Step 3

Solving the eq...

x4x2x2 -x+6
x2
(x4x +2x2-x+6)|
x4x22x+6 \.(x+2)
{multiply and divide by (x 2)
x+2
x+2
2x322x6
x+2)
(x+2)
-2x2x6
-(x+2)
(x+2)
3x+6(x+2)
2x22x+
(x+2)
(x 2x2-2x+3)x+2)
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x4x2x2 -x+6 x2 (x4x +2x2-x+6)| x4x22x+6 \.(x+2) {multiply and divide by (x 2) x+2 x+2 2x322x6 x+2) (x+2) -2x2x6 -(x+2) (x+2) 3x+6(x+2) 2x22x+ (x+2) (x 2x2-2x+3)x+2)

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Tagged in

Math

Calculus