Question

Asked Feb 17, 2019

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Find the slope of the tangent line to the graph of the function y=f(x)=1.5x2 at point x=2. Your answer should be precise to the third decimal.

Find the equation of this tangent line. You may want to use your answer from part 1.

Step 1

y=f(x)=1.5x^{2}

Slope of the tangent = dy / dx = f'(x) = 1.5(2x) = 3x

(Based on the dulr d(x^{n})/dx =nx^{n-1})

Step 2

Point given, at x = 2

y = 1.5x^{2} = 1.5 x 2^{2} = 6

Step 3

So, the point of tangency or point of contact P (x, y) = (2, 6)

And ...

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