Find the slope of the tangent line to the graph of the function y=f(x)=1.5x2 at point x=2. Your answer should be precise to the third decimal.
Find the equation of this tangent line. You may want to use your answer from part 1.
Slope of the tangent = dy / dx = f'(x) = 1.5(2x) = 3x
(Based on the dulr d(xn)/dx =nxn-1)
Point given, at x = 2
y = 1.5x2 = 1.5 x 22 = 6
So, the point of tangency or point of contact P (x, y) = (2, 6)
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