We Do: Solving Systems with EliminationWarm-up: Algebra TalkFind the solution for the system of equations.Step 1: Multiply eachequation by a suitablenumber so that the twoequations have either thesame leading or second10c + 15d = 25-10c - d= -7coefficient.Step 2: Subtract or add thesecond equation from thefirst.

Given equation is : 10c+15d=25 ....1-10c-d=-7 .....2 Multiply equation (1) by -10 and equation…

Find the solution for the system of equations. tep 1: Multiply each quation by a suitable umber so that the two quations have either the ame leading or second 10c + 15d = 25 %3D -10c - d = -7 oefficient. Step 2: Subtract or add the second equation from the irst.

Find the solution for the system of equations. tep 1: Multiply each quation by a suitable umber so that the two quations have either the ame leading or second 10c + 15d = 25 %3D -10c - d = -7 oefficient. Step 2: Subtract or add the second equation from the irst.

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018

18th Edition

ISBN:9780079039897

Author:Carter

Publisher:Carter

Chapter6: Systems Of Linear Equations And Inequalities

Section: Chapter Questions

Problem 51SGR

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Question

We Do: Solving Systems with Elimination
Warm-up: Algebra Talk
Find the solution for the system of equations.
Step 1: Multiply each
equation by a suitable
number so that the two
equations have either the
same leading or second
10c + 15d = 25
-10c - d
= -7
coefficient.
Step 2: Subtract or add the
second equation from the
first.

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