Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN: 9781285741550
Author: James Stewart
Publisher: Cengage Learning
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Question
Find the third degree Taylor polynomial T3 (x) centered at a = 1 for the function f(x)
○ T3(x) = 3 - 6x + 9x² − 12x³
T3(x) = 3 − 3x²
T3 (x) = 3 – 6(x − 1) + 18(x − 1)² – 72(x − 1)³
○ T3(x) = 3 + 6(x − 1) + 9(x − 1)² + 12(x − 1)³
○ T3 (x) = 3 – 6(x − 1) + 9(x − 1)² – 12(x − 1)³
=
3
x².
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Transcribed Image Text:Find the third degree Taylor polynomial T3 (x) centered at a = 1 for the function f(x) ○ T3(x) = 3 - 6x + 9x² − 12x³ T3(x) = 3 − 3x² T3 (x) = 3 – 6(x − 1) + 18(x − 1)² – 72(x − 1)³ ○ T3(x) = 3 + 6(x − 1) + 9(x − 1)² + 12(x − 1)³ ○ T3 (x) = 3 – 6(x − 1) + 9(x − 1)² – 12(x − 1)³ = 3 x².
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