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Find the volume of 0.130 M hydrochloric acid necessary to react completely with 1.55 g Al(OH)3.

Question

Find the volume of 0.130 M hydrochloric acid necessary to react completely with 1.55 g Al(OH)3.

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Step 1

Solution stoichiometry involves the calculation of concentration of solutions in the given conditions of volumes, moles etc.

Solution stoichiometry is mainly based on the calculation of moles and volumes. These two values are used to calculate the molarity of solution. The relation between moles, volume and molarity is as given below;

Moles of solute
Molarity
volume of solution in L
Mass of solute in g
Moles =
Molar mass of solute (g/mol)
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Moles of solute Molarity volume of solution in L Mass of solute in g Moles = Molar mass of solute (g/mol)

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Step 2

The balance reaction of Al(OH)3 with HCl is:

AICI 3H2O
Al(ОН), + ЗНCІ —
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AICI 3H2O Al(ОН), + ЗНCІ —

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Step 3

Calculate the moles of Al(OH)3

Mass of Al(OH)3 = 1.55 g 

Mol...

Mass of solute in g
Moles
Molar mass of solute (g/mol)
1.55 g
0.020 moles
Moles
78 g/mol
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Mass of solute in g Moles Molar mass of solute (g/mol) 1.55 g 0.020 moles Moles 78 g/mol

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