Question

Asked Sep 11, 2019

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Find the volume *V* of the described solid *S*.

The base of *S* is the region enclosed by the parabola
*x*−axis. Cross-sections perpendicular to the *y*−axis are squares.

y = 3 − 2x^{2}

and the V=?

Step 1

Given base of the solid S enclosed by parabola y=3-2x^{2} and the x axis and cross-sections are perpendicular to the y axis are squares. So first find the cross-sectional area of solid and then integrate it along y axis to find the volume.

Step 2

Cross-sectional area is in the form of Squares with side 2x and width dx is given by

Step 3

For limit of integration along y axis, put x=0 we get y=3 and also y is bounded below by ...

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