Question
Asked Oct 16, 2019
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finding a equation for a line thats perpendicular to y=-2x+2 but goes through (1,-12)? 

 

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Expert Answer

Step 1

Consider the given line equation

y=-2x 2
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y=-2x 2

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Step 2

Then slope of this line

Now the slope of line perpendicular to given line
m
2
TETN
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Now the slope of line perpendicular to given line m 2 TETN

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Step 3

Now the perpendicular line passing through the point ...

(у-у) -m, (х-*)
(у-12):
(х+1)
2
%3D —х— 1
2у - 24
2у +x-23 %3D0
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(у-у) -m, (х-*) (у-12): (х+1) 2 %3D —х— 1 2у - 24 2у +x-23 %3D0

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