For 1.25 mol of an ideal gas, Pexternal = P = 350 x 103 pa. The temperature is changed from 135°C to 21.2°C, and Cv,m = 3R/2. Calculate q, w, ∆U, and ∆H .
For 1.25 mol of an ideal gas, Pexternal = P = 350 x 103 pa. The temperature is changed from 135°C to 21.2°C, and Cv,m = 3R/2. Calculate q, w, ∆U, and ∆H .
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Chapter6: Thermochemisty
Section: Chapter Questions
Problem 6.50QP: An ideal gas expands isothermally (at constant temperature). The internal energy of an ideal gas...
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2. For 1.25 mol of an ideal gas, Pexternal = P = 350 x 103 pa. The
temperature is changed from 135°C to 21.2°C, and Cv,m = 3R/2.
Calculate q, w, ∆U, and ∆H .
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