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For each set of values, calculate the missing variable using the ideal gas equation. ????Set 1264.5 kPa1.69 L36.1 ∘C?1Set 2302 kPa2382 mL?23.23 molSet 3?30.0250 m3288 K1.08 molSet 4104 kPa?4303 K5.26 mol     ?1=  _________________ mol                        ?2= _________K?3=________________kPa?4=_________________L

Question

For each set of values, calculate the missing variable using the ideal gas equation.

 

?

?

?

?

Set 1

264.5 kPa

1.69 L

36.1 ∘C

?1

Set 2

302 kPa

2382 mL

?2

3.23 mol

Set 3

?3

0.0250 m3

288 K

1.08 mol

Set 4

104 kPa

?4

303 K

5.26 mol

 

 

 

 

 

?1=  _________________ mol                        

?2= _________K

?3=________________kPa

?4=_________________L

check_circleAnswer
Step 1

For Set 1: Moles is calculated as follows,

РУ %3
nRT
(264.5kPa) 1.69L) = (n)(8.314472 L.kPa.K-1.mol(36.1+273 )K
447.005kPa.L
(n)
8.314472L.kPa.K-l.mol"|309.1K
n 0.173m oles
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РУ %3 nRT (264.5kPa) 1.69L) = (n)(8.314472 L.kPa.K-1.mol(36.1+273 )K 447.005kPa.L (n) 8.314472L.kPa.K-l.mol"|309.1K n 0.173m oles

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Step 2

For Set 2: Temperature is calculated as follows,

PV
nRT
(302kPa) (2.382L ) = (3.23 mol) 8.314472L.kPa.Kl.molT
=
719.364kPa.L
(T)
8.314472L.kPa.K1.mol(3.23 mol)
T 26.79K
help_outline

Image Transcriptionclose

PV nRT (302kPa) (2.382L ) = (3.23 mol) 8.314472L.kPa.Kl.molT = 719.364kPa.L (T) 8.314472L.kPa.K1.mol(3.23 mol) T 26.79K

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Step 3

For Set 3: Pressure is cal...

PV nRT
(P)(25L) (1.08 mol)8.314472L.kPa.Kmol(288K)
(1.08 mol 8.314472L.kPa.K~mol(288K)
(P)=
(25L)
P 103.45kPa
help_outline

Image Transcriptionclose

PV nRT (P)(25L) (1.08 mol)8.314472L.kPa.Kmol(288K) (1.08 mol 8.314472L.kPa.K~mol(288K) (P)= (25L) P 103.45kPa

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