For Exercise, solve the equation. V7x + 8 = x + 2

Q: Solve the equation: (x - 2)2 = 20

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Q: For Exercise, solve the equation. 2 3 15

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Q: Solve for x and write the solution set x2-3x-18<0

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Q: For Exercise, make an appropriate substitution and solve the equation. 4 + 1 = 0 -- х

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Q: solve the equation. √(2x) = x - 4

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Q: For Exercise, solve the equation. (x2− 4)2 − 7(x2 − 4) − 60 = 0

A: Given:

Q: For Exercise, solve the equation. 10w2/3 10

A: To solve the given equation.

Q: Q1\ solve the equation: (x y + x² ) ỹ - y² = 0

A: NOTE-1 (According to our guidelines we can answer only  first question and rest can be reposted.)…

Q: For Exercise, solve the equation. V5 = 5'

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Q: For Exercise, solve the equation. -2V3m + 4 – 3 = 5

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Q: (g) y+1 = Yk + 6. %3D

A: The 1st order differential equation is            yk+12=yk+6

Q: solve the equation fo x. 5x=(3x-2)(m+4)

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Q: For Exercise, solve for the indicated variable.5x + y = −18 for y

A: Consider the given equation.

Q: For Exercise, solve the equation. 2x(x + 2) = 5x + 7

A: Given: The equation

Q: For Exercise, solve the equation. V3x + 1 = 11

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Q: For Exercise, solve the equation. V2n + 29 + 3 = n

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Q: Solve the equation 4 x² y" + 4 x y' – y = 0

A: The given opinions and incorrect. There can't be x in power. In particularly x(-x/2) can't be…

Q: For Exercise, solve the equation. | 2p*/5

A: Given

Q: For Exercise, solve the equation. 4 -2 5z - 3 4z + 7

A:

Q: Solve the linear equation: 5 + (x - 2)/3 = ( x + 3)/8.

A: Given: 5+x-23=x+38 for solving given equation, we use transportation then take L.C.M. and solve it

Q: For Exercise, solve the equation. x + 1) - 2 3" 1) –

A: Given expression

Q: Solve the equation. |x - 1| = |3x + 2|

A: Given equation: x-1=3x+2 Solve Absolute Value. x-1=3x+2 We know either x−1=3x+2 or x−1=−(3x+2)

Q: For Exercise, use A = 2 and B = -4 and solve for X. 9. B - 4X = A

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Q: For Exercise, solve the equation. x + 3 :- 4 + 2 = 5х х

A: LCM of the denominators is =5x So to get rid of the fractions we multiply both sides by 5x.

Q: For Exercise, solve the equations. -w 2 3 2

A: Add 1/3 to both sides

Q: Solve the linear equation: 2x - 7 = 6 + x

A: 2x-7=6+x

Q: For Exercise, use A = -4 and solve for X 4 and B = -2. [6 A + 5X = B

A:

Q: For Exercise, solve the equation. 5m 3 т — 1 т + Зт — 4 т+4

A: Given,

Q: For Exercise, solve the equation. V4 – x – V2x + 1 = 0

A: Given equation

Q: For Exercise, solve the equation. V1 + Vx + Vx + 1 = 2

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Q: For Exercise, use A = and B = -4 -4 and solve for X. 6. 2A - B = 10X

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Q: For Exercise, solve the equation. т 2 + 1 2m + 1 т — 3

A: Given equation

Q: For Exercise, solve the equation. z + 5 5z + 3 20 4

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Q: solve the equation. √(x2 + 3x - 6) = x

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Q: For Exercise, solve the equation. 5 -2 2n + 1 Зл — 4

A: To solve the given equation.

Q: Solve the equation.

A: Given:  x2+13x+2=0Quadratic Formula: x=-b±b2-4ac2a-1=i∈ℂ

Q: Solve the equation3(X - 4) +2 X = 5 ( X + 3) - 27

A: given that     3(X - 4) +2 X = 5 ( X + 3) - 27

Q: For Exercise, solve the equation. V2t + 8 – t= 4

A: Given equation:

Q: x= - 7p+210 0<ps30

A: x=-7p+210Rp=-7p2+210p (c)  Differentiate the above revenue function with respect to p.…

Q: For Exercise, solve the equation. 2 –

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Q: For Exercise, solve the equation. 3 20 ||

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Q: Solve the linear equation:- (x +3)/6 = 3/8 +(x - 5)/4.

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Q: Mentally solve the equation. 2x - 3 = 0

A: To solve the equation: 2x-3=0 Solution: 2x-3=0⇒2x=3⇒2x2=32     (dividing both sides by 2)⇒x=32.

Q: For Exercise, solve the equation. /y + 7 – V4y + 5 = 0

A: Add 6th root of (4y+5)

Q: Solve the equation. 2x - 10(2-x) + 3 = 0

A: Given equation is: 2x-102-x+3=0 We have to solve this equation for x. Let us substitute, 2x=u

Q: For Exercise, make an appropriate substitution and solve the equation. 3 -4 (т — 3) 3 т

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Q: For Exercise, solve the equation. Vx + Vx + 2 = 3

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Q: For Exercise, solve the equation. 4v 10 = v + 5v – 25

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