Question
Asked Dec 23, 2019
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For Exercise, solve the system by using the addition method. 

3x+y=21

4x-2y=-2

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Expert Answer

Step 1

We have given

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3x² + y² = 21 → (1) 4x² – 2y² = -2 →(2) Multiply equation (1) with 2 on both sides, we get 6x² +2y² = 42 → (3)

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Step 2

Solve

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Adding equations (3) and (2), we get 6x² + 2y? = 42 4x? – 2y² = -2 10x? ,2 = 40 →x = 4 =x = +2

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Step 3

Substitute the values of x in equatio...

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For x = 2, 3(2)² + y² = 21 12 + y? = 21 y² = 9 y =13 For x = -2 3(-2)² + y² = 21 12+ y² = 21 y = 9 y = +3

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Math

Algebra