Question
Asked Oct 25, 2019
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For the chemical reaction

 

CaI2+2AgNO3⟶2AgI+Ca(NO3)2

what mass of silver iodide is produced from 3.77 mol of calcium iodide?

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Expert Answer

Step 1

Given:

3.77 mol of calcium iodide

The chemical reaction involved:

              CaI2+2AgNO3⟶2AgI+Ca(NO3)2

 

Step 2

Calculate the moles of AgI:

As per the balanced chemical equation,

1 mol. Of CaI2 can give ------------  2 mol. Of AgI

3.77 mol. Of CaI2 can give--------- ? mol. of AgI

On cross multiplication,

             &nb...

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