Question
Asked Oct 27, 2019
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For the circuit shown in the picture, a 20.0 ohms resistor is embedded in a large block of ice at 0.00 degrees Celsius, and the battery has negligible internal resistance. 

At what rate (in g/s) is this circuit melting the ice ? ( the latent heat of fusion for ice is 3.34•10^5 J/kg.) 

 

dm/dt = _______________ g/s

For the circuit shown in the figure (Figure 1) a 20.0-2
resistor is embedded in a large block of ice at 0.00 °C,
and the battery has negligible internal resistance.
Pa
At
Figure
1 of 1
>
Ice
20.0 Q
Provide F
45.0 V
15.0
10.0 Q
ww
20.0 Q
10.02
5.00Q
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For the circuit shown in the figure (Figure 1) a 20.0-2 resistor is embedded in a large block of ice at 0.00 °C, and the battery has negligible internal resistance. Pa At Figure 1 of 1 > Ice 20.0 Q Provide F 45.0 V 15.0 10.0 Q ww 20.0 Q 10.02 5.00Q

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Expert Answer

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2 Ratings
Step 1

the three resistances with 10.0 ohm, 5.00 ohm and 15.0 ohm are in series and hence the effective resistance are some  of three which is equal to 30.0 ohm.

the other three are in parallel. 

the effective resistance is given by, 

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- -|R

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Step 2

substitute the given values in the above equation to calculate the effective resitance of the parallel combination, 

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1 1 1 R 20.0 20.00 10.02 1 40.0 1 R 400.0 10.02 1 1 1 R 10.0 10.0 1 1 R 5.00 R = 5.00

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Step 3

the effective resistance in t...

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R.a =R +Ruries

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