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For the following reaction, 26.7 grams of sodium chloride are allowed to react with 65.4 grams of silver nitrate . sodium chloride(aq) + silver nitrate(aq) silver chloride(s) + sodium nitrate(aq)What is the maximum amount of silver chloride that can be formed? What is the FORMULA for the limiting reagent?What amount of the excess reagent remains after the reaction is complete?

Question

For the following reaction, 26.7 grams of sodium chloride are allowed to react with 65.4 grams of silver nitrate .

sodium chloride(aq) + silver nitrate(aq) silver chloride(s) + sodium nitrate(aq)

What is the maximum amount of silver chloride that can be formed? 

What is the FORMULA for the limiting reagent?

What amount of the excess reagent remains after the reaction is complete?

check_circleAnswer
Step 1

Given:

Mass of NaCl = 26.7 g.

Mass of AgNO3 = 65.4 g.

Step 2

Balanced chemical reaction is given by:

NaCl (aq) AgNO3 (aq)
AgCl (S) NaNO3 (aq)
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NaCl (aq) AgNO3 (aq) AgCl (S) NaNO3 (aq)

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Step 3

Calculating number of ...

Mass
Number of moles =
Molar mass
26.7 g
Number of moles
58.44 g/mol
Number of moles 0.457 moles.
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Mass Number of moles = Molar mass 26.7 g Number of moles 58.44 g/mol Number of moles 0.457 moles.

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