Asked Nov 8, 2019

For the following reaction, 3.09 grams of iron(II) chloride are mixed with 5.47E-2 moles of silver nitrate.

iron(II) chloride (aq) + silver nitrate (aq) iron(II) nitrate (aq) + silver chloride (s)

What is the FORMULA for the limiting reagent?




What is the maximum amount of silver chloride that can be formed? 


Expert Answer

Step 1


Mass of iron chloride = 3.09g

Moles of silve...

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