For the following reaction 3O₂(g) ⇌ 2O₃(g) Kc = 2.10 × 10⁻⁷ at a certain temperature. If [O₂] = 0.0365 M when at equilibrium, what is the equilibrium O₃ concentration? Answer ___ M
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For the following reaction 3O₂(g) ⇌ 2O₃(g) Kc = 2.10 × 10⁻⁷ at a certain temperature. If [O₂] = 0.0365 M when at equilibrium, what is the equilibrium O₃ concentration?
Answer ___ M
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- Questions from Lab: Equilibrium and Le Chatelier's Principle 1.Consider the chemical reaction: N2+ 3H2 yields 2NH3. The equilibrium constant is K = 6.0 x 10-2, and concentrations are as follows [H2] = 2.5 x 10-1 M, [N2] = 4.0 M, and [NH3] = 1.0 x 10-4 M. Is the reaction at equilibrium? If not, which direction would it shift? Show your calculations. 2. Given this reaction at equilibrium, C(s) + CO2(g) D 2CO(g) (∆H° = 119kJ), explain the changes that would occur when the following stresses are applied: a.CO is removed. b.Heat is removed. c.CO2 is added.question 13 The reaction Cl2(g) + F2(g) ⇌ 2ClF(g) has Kc = 1.0 ×109 at a certain temperature. If 1.0 mol Cl2 and 1.0 mol F2 are placed in a 1.0 L reaction vessel and allowed to react, then at equilibrium… Question 13 options: The system will contain only Cl2 and F2. [ClF] will be much larger than [Cl2] and [F2]. [ClF] will be nearly equal to [Cl2] and [F2]. [ClF] will be much less than [Cl2] and [F2]. The system will contain only ClF.The following system was set up and allowed to come to equilibrium: C2H2(g) + 2 H2(g) ⇌ C2H6(g) At equilibrium, the concentration of ethyne was 0.210 mol/L, the concentration of hydrogen gas was 0.830 mol/L. The value of the equilibrium constant for the reaction at that temperature is 8. 10. What was the concentration of the ethane in mol/L? Answer in mol/L to 3 decimal places.
- Which of the following expressions is the correct equilibrium-constant expression for the reaction below? HF (aq) + H2O (l) H3O+ (aq) + F- (aq) Group of answer choices [H3O+][F-] / [HF] [F-] / [HF] [HF][H2O] / [H3O+][F-] [H3O+][F-] / [HF][H2O] 1 / [HF]Question 52 The reaction 2HCl(g) ⇌ H2(g) + Cl2(g) has Kc = 3.2 × 10−34 at 25 °C. If the reaction vessel initially contains 0.0750 mol L−1 of HCl, what will be the concentrations of H2 and Cl2 at equilibrium?K=4.9x10-3 for the reaction CO2(g)+H2(g)⇄ CO(g)+H2O(g). If [CO2]=0.00025 M, [H2]=0.0010 M, & [CO]=0.000015 M, what is the concentration at equilibrium of H2O? Answer 8.2x10-5M I got 1.84x10^-14? Can someone explain this to me please.
- If the reaction below is initially at equilibrium. Answer the questions below based on the reaction. 2CO(g) + O2(g) ⇄ 2CO2(g) (a) What would you do to favor forward reaction? Give two conditions.________________________, ______________________ (b) What would you do to favor reverse reaction? Give three conditions ________________________, ____________________ ________________________Calculate the value of [N 2] eq if [H 2] eq = 2.0 M, [NH 3] eq = 0.5 M, and K c = 2. N 2(g) + 3 H 2(g) --> 2 NH 3(g) 0.016 M 0.062 M 0.40 M 0.031 M 62.5 MFor the reaction: 2NOCl(g) ⟷⟷ 2NO(g) + Cl2(g) If the reaction were allowed to reach equilibrium and you were to remove some Cl2(g), what would happen? [Check all that are correct.] Group of answer choices - Equilibrium would shift to the right. - Equilibrium would shift to the left. - The amount of NOCl(g) would increase. - The amount of NO(g) would increase.
- For the following hypothetical equilibrium, A + 2 B ⇄ C, what is the value of the equilibrium constant if the concentrations at equilibrium are [A] = 5.5 x 10–5 M, [B] = 4.2 x 10–2 M, and [C] = 3.4 x 10–3 M? (no scientific notation)Given the following reaction: 3 H2(g) + N2(g) <--> 2NH3(g) If the volume of the reaction is decreased, the reaction will shift to the {BLANK} to restore equilibrium. What is BLANK? a. left b. rightPhosgene (COCl2) is a potent chemical warfare agent that is now outlawed by international agreement. It decomposes by the reaction, COCl2=CO + Cl2. Kc=8.3*10^-4. Calculate the [COCl2] when 0.010mol of the phosgene decomposes and reaches equilibrium in a 10.0L flask. Report your phosgene concentration in decimal form, not scientific notation. Also, don't forget that your vessel is 10.0L, not 1L.