For the following reaction, draw the major organic product and select the best name for the organicreactant. If there is more than one major product, both may be drawn in the same box. (Indicatestereochemistry with the wedge and dash.) When drawing hydrogen atoms on a carbon atom, eitherinclude all hydrogen atoms or none on that carbon atom, or your structure may be marked incorrectHBrНаSelect the best name for the organic reactant:(Z)-3,4-dimethyl-4-pentene(E)-2,3-dimethyl-1-pentene(Z)-3,4-dimethyl-4-hexene(E)-3,4-dimethyl-2-hexene

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Asked Nov 15, 2019
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For the following reaction, draw the major organic product and select the best name for the organic
reactant. If there is more than one major product, both may be drawn in the same box. (Indicate
stereochemistry with the wedge and dash.) When drawing hydrogen atoms on a carbon atom, either
include all hydrogen atoms or none on that carbon atom, or your structure may be marked incorrect
HBr
На
Select the best name for the organic reactant:
(Z)-3,4-dimethyl-4-pentene
(E)-2,3-dimethyl-1-pentene
(Z)-3,4-dimethyl-4-hexene
(E)-3,4-dimethyl-2-hexene
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For the following reaction, draw the major organic product and select the best name for the organic reactant. If there is more than one major product, both may be drawn in the same box. (Indicate stereochemistry with the wedge and dash.) When drawing hydrogen atoms on a carbon atom, either include all hydrogen atoms or none on that carbon atom, or your structure may be marked incorrect HBr На Select the best name for the organic reactant: (Z)-3,4-dimethyl-4-pentene (E)-2,3-dimethyl-1-pentene (Z)-3,4-dimethyl-4-hexene (E)-3,4-dimethyl-2-hexene

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Expert Answer

Step 1

Markovnikov rule states that during addition of protic acid to an asymmetric alkene the halogen gets attached to that carbon which contains a smaller number of hydrogen substituents and hydrogen gets attached to that part which contains a greater number of hydrogen atoms.

Step 2

If two bulky groups are present on same side in an alkene then the stereochemistry of the molecule is Z whereas, if the two bulky groups are present on opposite side in an alkene then the stereochemistry of the molecule is E.

Step 3

In the given structure, first longest carbon chain is determined, and numbering is done from the carbon which gives lowest numbering to double bond and as there are 2 methyl groups are attached therefore, prefix di is used to tell the n...

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5 4 HH 6

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