Question
Asked Jul 29, 2019
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For the reaction

2 ICl(g) <==> I2(g) + Cl2(g)

the value of Kc = 0.110

Calculate the value of Kc for this second reaction below:

6 ICl(g) <==> 3 I2(g) + 3 Cl2(g)

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Expert Answer

Step 1

The reactions and the expressions to calculate the equilibrium constants is,

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(g) Cl, (g) I2]Cl] 0.110 [ICI (1) 2IC1(g) (2) 6ICI (g)31, ()+3Cl, (g) 3 K ICI

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Step 2

Comparing the equilibrium constant expressions, it is clear that Kc’=Kc3.

Step 3

Therefore, the equilibrium constant...

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3 к - (К.) K 3 (0.110) 1.33x103

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