For the reaction shown below, 325 mg of benzaldehyde, 90 mg of acetone, and excess sodium hydroxide are used to obtain 66.1 mg of dibenzalacetone. What is the percent yield of dibenzalacetone? NaOH benzaldehyde MW = 106 g/mol; acetone MW = 58.0 g/mol; sodium hydroxide MW = 40.0 g/mol; dibenzalacetone MW = 234 g/mol

Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter17: Conjugation And Molecular Orbital (mo) Theory
Section: Chapter Questions
Problem 12E
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Please help me I am working on some UNGRADED practice and was confused, I have an exam and just wanted to study

For the reaction shown below, 325 mg of
benzaldehyde, 90 mg of acetone, and excess sodium
hydroxide are used to obtain 66.1 mg of
dibenzalacetone. What is the percent yield of
dibenzalacetone?
NaOH
H.
benzaldehyde MW = 106 g/mol; acetone MW = 58.0
g/mol;
sodium hydroxide MW = 40.0 g/mol; dibenzalacetone
MW = 234 g/mol
Transcribed Image Text:For the reaction shown below, 325 mg of benzaldehyde, 90 mg of acetone, and excess sodium hydroxide are used to obtain 66.1 mg of dibenzalacetone. What is the percent yield of dibenzalacetone? NaOH H. benzaldehyde MW = 106 g/mol; acetone MW = 58.0 g/mol; sodium hydroxide MW = 40.0 g/mol; dibenzalacetone MW = 234 g/mol
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