For the situation in the figure below, use momentum conservation to determine (a) the magnitude and (b) the direction of the final velocity of ball 1 after the collision. The angle o = 43.0 °. v01 = 0.900 m/s m1 = 0.150 kg +y 나1 +x "02 = 0.540 m/s m2 = 0.260 kg /35.0 42 = 0.700 m/s (a) +y Vly Uflx (b) (a) Top view of two balls colliding on a horizontal surface. (b) This part of the drawing shows the x and y components of the velocity of ball 1 after the collision.

An 0.250kg object, going 2m/s, slides across a frictionless surface into another object (0.400kg) at rest. The 0.250kg object bounces backwards at a 135o angle from the other object going at 1.5o m/s. What is the magnitude and direction of the 0.400kg object after the collision?

As part of a carnival game, a mb=0.603 kgmb=0.603 kg ball is thrown at a stack of 16.8 cm16.8 cm tall, mo=0.343 kgmo=0.343 kg objects and hits with a perfectly horizontal velocity of vb,i=11.6 m/s.vb,i=11.6 m/s. Suppose that the ball strikes the topmost object. Immediately after the collision, the ball has a horizontal velocity of vb,f=3.60 m/svb,f=3.60 m/s in the same direction, the topmost object has an angular velocity of ωo=2.03 rad/sωo=2.03 rad/s about its center of mass, and all the remaining objects are undisturbed. Assume that the ball is not rotating and that the effect of the torque due to gravity during the collision is negligible. If the object's center of mass is located r=11.8 cmr=11.8 cm below the point where the ball hits, what is the moment of inertia IoIo of the object about its center of mass?   What is the center of mass velocity vo,cmvo,cm of the tall object immediately after it is struck?

Macmillan Learning An object of mass 3 M, moving in the +x direction at speed vo, breaks into two pieces of mass M and 2M as shown in the figure. If 0₁ = 69.0 and 02 = 22.0°, determine the final velocities U₁ and 2 of the resulting pieces in terms of vo. VI U2 = 1.155 Incorrect 1.4 VO VO 3M Vo 2M M 1/2₂2 = ? 0. V₁ = ?

A 1.99-kg particle has a velocity (2.05 i 2.99 ĵ) m/s, and a 3.01-kg particle has a velocity (1.09 1 + 6.08 j) m/s. (a) Find the velocity of the center of mass. î+ ₁) 1 m/s (b) Find the total momentum of the system. Î+ i) kg. m/s

In this problem, an astronaut is landes on the 6.1×1021 kg asteroid traveling at 9830 m/s and detonates a nuclear bomb. The asteroid breaks into two pieces of equal mass. One piece will fly off at an angle of 30∘ and speed 9700 m/s. What will be the speed and angle of the second piece?

A radioactive nucleus at rest decays into a second nucleus, an electron, and a neutrino. The electron and neutrino are emitted at right angles and have momenta of Pe=9.67x10-23 kg. m/s and p = 5.99×10-23 kg. m/s. respectively. (Figure 1) Figure Pnuc nuc +y 0 Onuc Py Pe 1 of 1 +X Part A Determine the magnitude of the momentum of the second (recoiling) nucleus. Express your answer to three significant figures and include the appropriate units. Pnuc= Submit Part B Onuc = Submit μA 4 Provide Feedback Value Request Answer Determine the angle between the momentum of the electron and the momentum of the second (rec Express your answer using three significant figures. [VE| ΑΣΦ 1 → C Request Answer Units 1 ? ?

Q.10. A bullet of mass m = 20 g is fired horizontally into a wooden block, of mass M = 1 kg, resting on a horizontal table. The speed of the bullet just before reaching %3D the block is v, = 600 m/s. If the bullet imbeds in the block, then the speed of the (bullet, block) system immediately after the collision is: a. v = 0 b. v = 14.634 m/s %3D M c. v = 17.475 m/s d. v = 11.765 m/s m + M

A 0.0250 kg bullet moving horizontally at 500 m/s embeds itself into an initially stationary 0.500 kg block.(a) What is their velocity just after the collision?m/s(b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity?m/s(c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far does this combination travel before stopping?m

A 0.0220 kg bullet moving horizontally at 500 m/s embeds itself into an initially stationary 0.500 kg block. (a) What is their velocity just after the collision?m/s(b) The bullet-embedded block slides 8.0 m on a horizontal surface with a 0.30 kinetic coefficient of friction. Now what is its velocity?m/s(c) The bullet-embedded block now strikes and sticks to a stationary 2.00 kg block. How far does this combination travel before stopping?m