Asked Oct 21, 2019

Formic acid, HFor, has a Ka value of 1.8 x 10^-4. You need to prepare a buffer having a pH of 3.25 from 0.10 M HFor solution and a 0.10 M NaFor solution. How many mL of the NaFor solution should you add to 20 mL of the 0.10 M HFor solution to make your buffer? 


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Given that p H solution of buffer to be prepared is 3.25. The acid dissociation constant, Ka is 1.8x10. Using the p H and Ka value, the mole ratio of NaF to HF can be determined salt PH-pКa+1og| acid NaF 3.25=log (Ka) +log HF NaF 3.25=-log (1.8x10)+log HF NaF 3.25 3.75+log HF NaF log HF =-0.5 NaF 0.3162 HЕ


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